Here, n = 10, p = 0.46, (1 - p) = 0.54 and x = 2
As per binomial distribution formula P(X = x) = nCx * p^x * (1 -
p)^(n - x)
We need to calculate P(X >= 2).
P(X >= 2) = (10C2 * 0.46^2 * 0.54^8) + (10C3 * 0.46^3 * 0.54^7)
+ (10C4 * 0.46^4 * 0.54^6) + (10C5 * 0.46^5 * 0.54^5) + (10C6 *
0.46^6 * 0.54^4) + (10C7 * 0.46^7 * 0.54^3) + (10C8 * 0.46^8 *
0.54^2) + (10C9 * 0.46^9 * 0.54^1) + (10C10 * 0.46^10 *
0.54^0)
P(X >= 2) = 0.0688 + 0.1564 + 0.2331 + 0.2383 + 0.1692 + 0.0824
+ 0.0263 + 0.005 + 0.0004
P(X >= 2) = 0.9799
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