Using both type I and type II region evaluate double integral SSR xy dĀ, with the...
Calculate the integral using the type II method after the transformation: = SSR xy dA, where R is the region in the first quadrant bounded by the lines y = x, y = 3x, and the hyperbolas xy = 1, xy = 3. Make the transformation x = u/v and y = v
Calculate the integral: I = SSR xy dA, where R is the region in the first quadrant bounded by the lines y = x, y = 3x, and the hyperbolas xy = 1, xy = 3. Make the transformation x = u/v and y = v If you have done a type I integration, can you give an expression for a type II (no calculation) integral and vice-versa, or can you explain why one integral is preferable over the other.
3. Draw the region D and evaluate the double integral using polar coordinates. dA, D= {(x, y)| x2 + y² <1, x +y > 1} (b) sin(x2 + y2)dA, D is in the third quadrant enclosed by D r? + y2 = 7, x² + y2 = 24, y = 1, y = V3r.
(7) (10 points) Change the Cartesian integral lent polar integral, and then evaluate it. Г y dx dy into an equiva- (8) (10 points) Evaluate the double integral SSR xʻy dĀ, where the region R is bounded by the lines x = 0, x = 2, y = x, and y = x +4, using the transfor- mation x = 2u, y = 40 + 2u.
3. Draw the region D and evaluate the double integral using polar coordinates. (a) SI x + y dA, x2 + y2 D= {(x, y)| x2 + y2 < 1, x + y > 1} D (b) ſ sin(x2 + y2)dA, D is in the third quadrant enclosed by m2 + y2 = 71, x2 + y2 = 27, y=x, y= V3x.
need asap Calculate the integral using the type II method after the transformation: I = xy dA, where R is the region in the first quadrant bounded by the lines y = x, y = 3x, and the hyperbolas xy = 1, xy = 3. Make the transformation x = u/vand y = v
Evaluate the double integral I = Slo xy dA where D is the triangular region with vertices (0,0), (1,0), (0,6).
Calculate the integral using the type II method after the transformation: 1 = SR xy da, where R is the region in the first quadrant bounded by the lines y = x, y = 3x, and the hyperbolas xy = 1, xy = 3. Make the transformation x = u/v and y = v
set up iterated integrals for both orders of integration. then evaluate the double integral using the easier order and explain why it's easier. D y dA, D is bounded by y = x - 2, x=y2 (the D next to the double integral should be under the integral. I don't know how to put it in the right spot.
2. Set up and evaluate the volume integral for the region whose base D lies in the first quadrant in the xy plane and whose top is bounded by x + y + z = 4. 3. Find the volume that is enclosed by both the cone z = x2 + y2 and the sphere x2 + y2 + z = 2