A 0.060-kg tennis ball, moving with a speed of 5.44 m/s , has a head-on collision with a 0.085-kg ball initially moving in the same direction at a speed of 3.16 m/s . Assume that the collision is perfectly elastic.
1) Determine the speed of the 0.060-
kgball after the collision.
2) Determine the speed of the 0.085-
kgball after the collision.
given that
m1 = 0.06 kg
u1 = 5.44 m/s
m2 = 0.085 kg
u2 = 3.16 m/sec
in perfectly elastic collision
v1 = (m1-m2)*u1/(m1+m2) + (2*m2*u2/(m1+m2)
v1 = ((0.06-0.085)*5.44/(0.06+0.085)) +
((2*0.085*3.16)/(0.06+0.085))
v1 = 2.77 m/s is the answer for 1)
v2 = 2*m1*u1/(m1+m2) + (m2-m1)*u2/(m1+m2)
v2 = ((2*0.06*5.44)/(0.06+0.085)) + ((0.085-0.06)*3.16/(0.06+0.085))
v2 = 5.04 m/s is the answer for 2)
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