Question

Consider the circuit shown below. V, changes from 0 V to 1.5 V at t = 0 and remains at 1.5V. The transmission line has air between the conductors. {= 6 cm Rs=1502 WO w RL= 450 12 Vo=1.5V ( Zo=502 a) Find the following reflection coefficients: i. Tų (refl. coeff. at the load) ii. I's (refl. coeff. at the source) b) Complete the bounce diagram below by finding the values of the voltage pulses Vi+, Vi V2+, V2, V3+ Vz, V4, V4. Vit = < V1 = V; = | V = V = V =

Answer 1

Reflection coefficient al load n clorcent look's lire * Bonse H1 Į Z=4502 we know reflection coefficient formula is T = 22-25 (:22=4502) 2 g = 2g =502 242s 450-50 450150 IF = 0.8 Reflection coefficient out Source :- H zo sona SZ1502 reflection coefficient of source r. 22-26 se zutzs ZL= 1502 Zo=502 ro = 150-50 - 150750 100 100 20 16 = 015 ] P=0.5 {=008 a = 105 - 1.580:8 l 1, 2X0.5 No nib -0.680.8 0.48 V2 ou8x0.5 - 120.24 0.2480.8 0.192X0.57 0.096 your VA 0.096 .0768 0.074 0.0768x0.5 / k -. 0.0384 V = 102 V₂ = 0.48 V3 - 0.192 vet = 0.096 Vis 0.0768 Scanned with CamScanner

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