Question

Two coils have mutual inductance of M = 3.20×10−4 H . The current I1 in the first coil increases at a uniform rate of 860 A/s .

A) What is the magnitude of the induced emf in the second coil? (answer in V)

B) Suppose that the current described is in the second coil rather than the first. What is the magnitude of the induced emf in the first coil? (answer in V)

Answer 1

Solution We are gwen Mutual inductance between two cocke M = 3.20 x 10-411 Now, Lux in second coll due to first wil & P = MI & Emf induced in second coil 7 &= dq = Melli C (magnitude) २ व 9. &= mdi . at Now 1 = 860 Als 860 AG :&= (3.20x104)(860) - 10.28 Vouts 6. Now if woent is second coil's now,

Hence this time, IZ = $60 MIS dt Hence M I flux in foast wil , 01= due to second coil Hence magnitude of emf induced in forst coil due to sourd coil, & del = mdi= (3.20x154)(860) T&i= 0.28 volts Hope you like my solution & my efforts &