Question

I have 3 questions, please show work so I can learn how to do the problems on my own.

1. An electric field E in N/C, right causes the m in grams ball in the figure to hang at a T degree angle. What is the charge on the ball in nanoCoulombs?

2. What is the magnetic flux through the loop shown in the figure? B=5.49 T, G=1.73 T and L=46.62 cm.

3. A straight wire carrying a current of 40.27 A lies along the axis of a 9.34 cm-diameter solenoid. The solenoid is 0.68 m long and has 221.06 turns carrying a current of 6.18 A.What is the magnitude of the magnetic field, in mT, 1.82 cm from the wire?

Answer 1

you have asked 3 question.As per guidelines i can only answer one.For first 2 figure is not given,so i will solve 3 rd one.

The field inside the solenoid is given by where: μ is the permeability of free space (4"T*10^-7), N is the number of turns, l is the current in each turn, and h is the height of the coil Inside the solenoid, B is a constant: B-S = (4T10^-7)*22 1.06*6.1 8.68 = 2.52*10^-3 T-2.52 nT This B field is aligned with the axis of the solenoid The B field due to the current in the wire on the axis of the solenoid is: Bow = μ102Tr) = (4"m*1 0^-7)"40.27/(2T·0467) = 1 72.4° 10^-6 T = 0.1 720nT This field (from the right hand rule) is in a direction tangential to the wire, and therefore at right angles to the solenoid field. These two can be combined to find the magnitude by using the Pythagorean equation: BI = sqrt[ (Bour2 + (B-s)^2 ] = sqrt 2.52"2 + .1722) m-2.5 mT At 1.82cm, the specified point is outside of the 9.34cm diameter solenoid. According to the theory, the field outside of an ideal solenoid is zero, so the field that exists is solely due to the wire 4424.2*10-7 T 0.442 mT-answer