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Near the Earth's surface, a horizontal wire of length 1.0 m is place between the poles...

Near the Earth's surface, a horizontal wire of length 1.0 m is place between the poles of a horizontal horseshoe magnet. The wire has a mass of 0.0033 kg and is connected to a source of potential difference by two very light wires attached at opposite ends. There is an electric current of 1.0 A in the wire. The wire is in static equilibrium. The width of each pole is 0.050 m. What is the direction of the electric current in the wire?

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Answer #1

Here we will use Lorentz law as below,

F= L(I x B)

Here since the wire is steady, by Newton’s second law Fg will balance by Fb(manetic force on the wire)

Thus Fb is upward. And the situation is shown in the below diagram.

Thus direction of the current must be along z axis or out of the page.

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