Question

Draw structures for compounds that meet these descriptions: C2H60; one singlet C3H7C1; one doublet and one septet C4H8C120; two triplets C4H802; one singlet, one triplet, and one quartet

Answer 1

C_2H_6O: - CH_3-o-CH_3 rightarrow Both CH_3 groups have same environment. Hence which gives only one singlet in NMR spectnorlogy. C_3H_7cl: - H_3c-c-CH_3 rightarrow Both CH_3 groups have the same environment hence which gives only one siglet, The Hydrogen attached the carbon containing CH gives one sptet with coupling C_4H_8Cl_2: - cl-CH_2-CH_2-o-CH_2-CH_2-cl-CH_2 spin-spin coupling, which gives two triplets C_4H_8O_2: - these 3 types of pustons are prefant which gives one singlet, one triplet and one quartet