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Question 1 34 points As shown in the below figure the link AB has a constant angular velocity ) = 34 rad/s. Find out the: (a)

Please use the following formula sheet:

Formula Sheet Newton Equations u du = a ds s ds = g ds Cartesian Coordinates r = xi + yj v = r = či + ýj a = v = f = $i+yj Ta

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Answer #1

The angular velocities and angular accelerations are calculated using the given formulas above.

(a) The angular velocity of the rod BD (\omegaBD) = 45.33 rad/sec

(b) The angular velocity of the rod DE (\omegaDE) = 16 rad/sec

(c) The angular acceleration of the rod BD (\alphaBD) = 1520.925 rad/sec2

(d) The angular acceleration of the rod DE (\alphaDE) = 1982.268 rad/sec2

Givey WAB 34 Maafsee writing vector forms ß 굿 0.2? + 0.3 Men 30-3 î + o. 0.075 A de -0.425 DE +0.425 We how that, WART TBA =-0.075 W BO - 0.425 WDR 10.2 0.3 WBO - 0.425 WOE - 6.8. 6 solving, we get BD- us.333 rad/ge DE -16 radoc BO 45.33 rad/sec (cl2 a = a + XBOX F/ 10/B Bp = (231.2 ? - 34687) + Root (0.21 +0.075) - (45.33) ² (0.37 +0.075 0.075 2 - (-231.2- 616-333-0.075soling Ecation ③ & & , we get مرا 0.3 & BD +0.925 XDE = 392.133 0.07S XBO ours & DE 956.5332 BD - 1520.925 red/sec2 DE- 1982

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Please use the following formula sheet: Question 1 34 points As shown in the below figure...
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