IN C ONLY PLZ (read the instruction carefully plz)
You will implement the following functions:
List * initIntegerList( ) // Return empty list
int insertAtHead(int k, List*) // Insert k at head
int insertAtTail(int k, List*) // Insert k at tail
int removeHead(List *) // Remove head and return its key
int getListSize(List *) // Return number of elements in list
void printHead(List *) // Print key in head
void moveHeadToTail(List *) // Move key at head to tail
This doesn’t seem so bad – and it isn’t. However, there is a performance requirement that must be satisfied: all of the functions must take only a constant amount of time independent of the length of the list, i.e., they must all have O(1) complexity. Does this make things much more difficult? No, you just need to define a struct (List) that contains a pointer to the head of a linked list; a pointer to the tail of the list; and an integer containing the number of items/keys in the list. (Note that nodes in the linked list will not be List structs.) The information in the List struct is what will allow all operations to be satisfied in O(1) time.
Note that the above prototypes impose restrictions on how you handle potential error conditions, e.g., if the user tries to remove the head of an empty list, so you will need to document those situations for the user. For example, the function printHead will need documentation telling the user that nothing is printed if the list is empty. The two insert functions, however, have integer return values that can be used for error codes.
// C program to implement Linked list operations in O(1) time
#include <stdio.h>
#include <stdlib.h>
// structure to represent a node in the linked list
typedef struct Node
{
int data;
struct Node *next;
}Node;
// structure to represent the list
typedef struct List
{
Node *head;
Node *tail;
int size;
}List;
// function prototype
List * initIntegerList( ); // Return empty list
int insertAtHead(int k, List*); // Insert k at head
int insertAtTail(int k, List*); // Insert k at tail
int removeHead(List *); // Remove head and return its key
int getListSize(List *); // Return number of elements in list
void printHead(List *); // Print key in head
void moveHeadToTail(List *); // Move key at head to tail
int main(void) {
printf("\nInsert At Head :");
List *list = initIntegerList();
int result;
if(list != NULL)
{
int i;
for(i=1;i<=5;i++ )
{
result = insertAtHead(i,list);
if(result == 0)
{
exit(1);
}
printHead(list);
}
printf("\nInsert At Tail :");
for(i=6;i<=10;i++)
{
result = insertAtTail(i,list);
if(result == 0)
exit(1);
}
printHead(list);
printf("\nSize : %d",getListSize(list));
printf("\nMove Head to Tail :");
for(i=0;i<getListSize(list);i++)
{
printHead(list);
moveHeadToTail(list);
}
printHead(list);
printf("\nSize : %d",getListSize(list));
printf("\nRemove Head :");
while(getListSize(list) > 0)
{
//printHead(list);
printf("\nRemoved : %d",removeHead(list));
}
}
return EXIT_SUCCESS;
}
// function that creates and returns a new empty list, returns NULL if memory allocation failed
List * initIntegerList( ) // Return empty list
{
// create a new List
List *list = (List*)malloc(sizeof(List));
// check if memory is allocated successfully
if(list != NULL)
{
// initialize head and tail to NULL and set size to 0
list->head = NULL;
list->tail = NULL;
list->size = 0;
}
return list; // return list
}
// function to insert the node at the head of the list
// returns 1 if insertion is successful else 0
int insertAtHead(int k, List *list) // Insert k at head
{
Node *node = (Node*)malloc(sizeof(Node)); // create a new node to contain k
// if memory allocation is successful
if(node != NULL)
{
// insert the node at head
node->data = k;
node->next = list->head;
list->head = node;
if(list->tail == NULL)
list->tail = node;
list->size++;
return 1; // insertion successful
}
return 0; // insertion unsuccessful
}
// function to insert a node at the tail
// returns 1 if insertion is successful else 0
int insertAtTail(int k, List *list) // Insert k at tail
{
// create a new node to contain k
Node *node = (Node*)malloc(sizeof(Node));
// if memory allocation is successful
if(node != NULL)
{
// insert node at the tail
node->data = k;
node->next = NULL;
if(list->tail !=NULL)
{
list->tail->next = node;
}else
list->head = node;
list->tail = node;
list->size++;
return 1; // insertion successful
}
return 0; // insertion unsuccessful
}
// function to remove and return the value at the head of the list
// return the key value if deletion is successful else returns -999
int removeHead(List *list) // Remove head and return its key
{
if(list->head == NULL) // empty list
{
printf("\nEmpty list");
return -999;
}
else
{
// delete the node at the head
int k = list->head->data;
Node *node = list->head;
list->head = list->head->next;
if(list->head == NULL)
list->tail = NULL;
list->size--;
free(node);
return k;
}
}
// function to return the size of the list
int getListSize(List *list) // Return number of elements in list
{
return list->size;
}
// function to print the value at the head of the list
void printHead(List *list) // Print key in head
{
if(list->head == NULL) // empty list
printf("\nEmpty list");
else // non-empty list
printf("\nHead : %d",list->head->data);
}
// function to move the node at head to the tail
void moveHeadToTail(List *list) // Move key at head to tail
{
if(list->head == NULL) // empty list
printf("\nEmpty list");
else
{
if(list->head->next != NULL) // more than 1 node
{
// move the head node to tail
Node *node = list->head;
list->head = list->head->next;
node->next = NULL;
list->tail->next = node;
list->tail = node;
}else // 1 node so no movement
printf("\nList has only one element");
}
}
//end of program
Output:
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