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3. [0/1 Points] DETAILS PREVIOUS ANSWERS Consider the figure. Find a if A = 14a. X a = 7 O с a B А D B Need Help? Read It Talk to a Tutor

Answer 1

3. Here, B A LEAD = 148. LACD = x and LADC=90 .. for the forlangle DADC LEAD & LACD + LADC =180° 7 14Xtat 90° = 180° 7 152 = 180-909 90° 6° 27 x = 15 6° E Х For this case, P B = 50° Drawing B a horizontal line cd parallel to the horizontal AB. Then AB || CD and AX is interceptor .: LBAC and Locx are similar angle. LBAC = LDCX = x Now, vertical post EC is perpendicular to horizontal CD .. LE CD = 90° Angle between EC and walkway AX is ß = LECX, LECX + LDCX= LECD + B+ 2 = 90° a = 90°-ß = 90°- 50° 2400 ..x=40°

a=41 ibal DABC is a sight triangle. Ja xtb So, AC B A 2 AB toc = 7 x + (a+b) = (va) 2 7 X + (x+1)2 = (141) =+ +22+) = 41 > ax+ 2x-40=0 2x + 100-8a-4020 27 22 (2+5) – 8(x+5)=0 -> (92-3) (a+s) = 0 → x=-5 at5=0 not possible as a is measure of a side of a triangle 22-950 my 2 = 4 x=4 B Be=3 BD=5 AD=4. from ABCD, (BC) 7 (DC) = (BD) 7 V (BD) 7 (BC)2 De a ✓st.gr - 525-9 r DC Vi6 DC = A 7 DC 24 AC = ADt Dc = 4+4= 8 from a ABC, 64+9=73 (AB) = (A + B r = = 82 + 3 Y AB V73. | AB = 873