a] here speed = area under a-t graph
= 3*[4-1]
= 9 m/s
b] speed at the end of t=6 s is 9-1*1 = 8 m/s
so distance travelled = 0.5*3*(4-1)^2 + 9*1 + 9*(6-5) - 0.5*1*(6-5)^2
= 31 m
c] speed at t= 10s, v = 9-1+4-2 = 10 m/s
distance travelled in given time = 10* [14-10]
= 40 m
d] distance covered = 9*(6-5) - 0.5*1*(6-5)^2 + 8*(8-6)+0.5*2*(8-6)^2 + 12*(9-8) -0.5*1*(9-8)^2
= 40 m
aaverage speed = distance/time = 40m/4s
= 10 m/s answer
A car is initially at rest on a straight road. The histogram below shows the car's...
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