Question

19) A3 cm tall object is 12 cm in front of a concave mirror with the focal length of 24 cm. a. Find the position of the image? b. Explain if the image is real or virtual? c. Is the image formed in front or behind the mirror and why? d. How tall is the image? c. Explain if the image is upright or inverted? f. Is the image bigger or smaller than the object and why?

Answer 1

(19.) Thosem Sheight and of object 12cm - 24cm 24 -12 12 2- 24 24 focal length is f= -24cm. Object distance is u=-12cm @ If image distance és v then from mirror formula: ttu = + t = 1 h st >V= 24cm i Image is at a distance of 240m behind the Sence image is behind the mirror and object is in front of merror so, image is vestual. from sign convension -ve is taken as infront of memor and the is taken as behind the mirror. since image v is tve, so image es behind the memon a magnification is ma---24 meror. distance =+2 и .12 Im= +2 If height of image is hi then, m=hi (cs Scanned with mxho=2x3 cm h=6cm no

Since magnification is the so image should be of same sence as the object. - Image is upright. Since magnitude of magprilicetom is greater than 1, image is bigger than the ob object. Shaee W CS CamScanner