Question

What are the R and S configurations of each of these molecules

oH Ho Y OH 0 40 NH2 NH2 NH2 애 신 NH₂

Answer 1

In C2 centre the order of priority of the groups -NH2) – COOH 9 - CHCOM) CH3 ) -H обH 20 HA 04 H Atz &.l. 2 the rule is - if the heart priority group is in the vertical position and 23 is clockwise then the configuration will be 'R if anyone is changed then it become s', and if two are changed then it remain as At 2 centre (4 is in horizontal and 1 2 3 clockwise, so c2 centre in 'S', it in. > Now, at 3 centre the priority order is a -OH) CH (N2) (COOH) 7 - CH3) CooH H AN OH Н нэ 4's in horizontal position and 1 2 3 is ante- clockwise. So, 3 centre is 'R' OH -Olt TR mto

014 .04 Mt 2 The fischer projection of this molecule is a coot Mt2 2 2 OH 4 CH3 At 22 centre Coolt H MA2 4 - horizontal 1*2*3- anticlockwise H 04 So, 02 is 'R' configuraĥion . CH 3 At 3 centre СТОН 14 -Mt2 OH o H (4) CH3 4 horizontal 172- 3 → anticlockwise So, 3 centre is R configuration OH R -OH R Mtz

OH Mt2 the Fischer projection of this molecule is Icoola 2 H Hen 3 H HO- 4 CH3 At c2 centre coolt HN B # I O 4 horizontal 1+2 3 clockwise (2 centre in s configuration so, etty At 3 centre coot M HO ORIO 0 So, 4 horizontal 123 clockwise (3 contre in is configuration. -OH S mtz

OH Phot Mt2 - The fischer projection of this molecule is coot н 2 MA2 HOC 2 H CH3 At 2 centre COOH H MAZ 4 horizontal .H HO 1-2-3 anticlockwise :.02 centre is 'R' confn. CH3 At 3 centre COOH H -Mt2 14 HO CH 4 horizontal ₂23 clockwise Therefore c3 centres 'S configuration -ОН mto