Question

and final values. Does own (and hence can be solved Guided Problem 5.4 Burrowing bullet A gun that has a muzzle velocity of 600 m/s is used to fire a 12.0-g bullet horizontally into a 4.00-kg block of wood initially at rest. The bullet passes completely through the block, with negligible loss of inertia to either object. After the collision, the block slides at 1.20 m/s in the direction of the bullet's motion. What is the change in internal energy in the bullet-block system? Ignore any effects due to friction between the block and the surface over which it slides. GETTING STARTED 1. Which objects should you include in your system? Draw a sys- tem diagram for these objects. 2. Which conservation laws apply here: momentum, energy, or both? How could you represent what happens to these quanti- ties graphically? DEVISE PLAN 3. Write equations relating the initial and final ve any equation have a single unknown (and hence a immediately)? 4. What is the relationship between the change in inta and the change in kinetic energy? 3 EXECUTE PLAN EVALUATE RESULT ange in internal energy

Answer 1

Let's calculate the final speed of the bullet applying the conservation of linear momentum: Po = PE mv = mv. + MV Using the given data: (12 x 10-3)(600) = (12 x 10-3)Vf + (4)(1.20) Then: Vq = 200 The change in internal energy is the change in kinetic energy: т AU = ax = = mv2 - 3 mv} = 3 (12 x 10-2)(600)2 – (12 x 10-9)(200)? AU = 1920 ]