There is a proton and antiproton that collide head-on with equal kinetic energies. Two gamma rays with wavelengths of 1 fm are produced. Calculate the Kinetic energy of the proton.
2K.E. = hc / lambda
2 x K.E = 6.63 x 10-34 x 3 x10^8 / (1 x 10-15 )
K.E. = 9.945 x 10-11 J
KE = h*c/lamda
= 6.625*10^-34*3*10^8/1*10^-15
= 1.9875*10^-10 J
= 1.24*10^9 eVolts
There is a proton and antiproton that collide head-on with equal kinetic energies. Two gamma rays...
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