Question

Period: Date: - Name: Lesli 9.3 H.SO. 2Al(OH), - Al-(50c)+ 3H0 . What is the ratio of H.to ALSO.)? What about Al(OH) to H02 L: 19 9 ->L How many liters Al(SO) is produced from 173 grams of ALLOH in the above reaction? 17.3 Imel 1 22.4 387.52 37.48 1789 2 llmol 156 In a laboratory investigation, you add 33.2 liters of H2SO4 to Al(OH)3 and produce how much water in liters? 33.2 3. The products of the following combustion reaction are captured from a hydrocarbon resulted in wate por and 440.00 g of CO2. 2 =2=X2 I CzH+3 02-_2_002+ 2 H20 4=H=2 61-0-33 1. How many moles of carbon dioxide are present after combustion? How many liters of water does the water vapor trap capture? w many grams of Oz are used in combusting the unknown sample?

from C and down please

Answer 1

Mole concept

Follow above flow chart for formulas used.

Multiply by Std. weight Mole Divide by 22.4 at STP - Volume Multiply by 22.4 at STP xivide by Standard Weight

22.4 3 H ₂ SO 4 + 2 Al(OH)3 Alz (Sou) z + 371 20 - (c) Giveni 33. 2 litre of H₂ Boy 33.2111 |3 | 22:44 - 133.2 l) 22.4 e 3) OR Moles of the son = 33.2 = 1.48 moles As Stoichiometry of 4,04 H, soy are dame, do moles of H₂SO4 will be equal to Ho. in. Volume is litire = 1.48 * 20.4. -33.21 » Hy +3 0 2 42 +240 (1.) Moles of coz & Given weight [Given weight: 440g] Molecular mass . Moles = 440 - 10 moles of lol 44 - (b) to find litres of water As stoichiometry of co & Ho are seme rie a so number of moles of coz is same as Ho. a. Moles of 40 = 10 moles - Volume = 10 x 22-4 = (224 I] (6.) To find grams of a used. Il moles of coa (with stoichiometry 2) is 10 moles, then moles of o (with Stoichiometry 3) is = 10 x 3 = 115 moles As, Weight = Moles x Molecular Mass 2 : 15 x 32 -1480 y 9 ] Molecular Mals of a = 32 g/mol