ZEROS OF POLYNOMIAL FUNCTIONS 1. Find a polynomial function f(x) of degree 3 that has the...
Write a polynomial f(x) that satisfies the given conditions. Polynomial of lowest degree with zeros of (multiplicity 2) and 1 (multiplicity 1) and with f(0) = -2. 4 $(x) = a
Find a polynomial function of degree 3 with real coefficients that satisfies the given conditions. See Example 4. 5) Zeros of 2 f (x) = - 3 and 5: f(3) = 6
Find a polynomial f (x) of degree 3 with real coefficients and the following zeros. -4, -2+i X ?
Find the complete factored form of the polynomial f(x) that satisfies the given conditions. Degree 3, leading coefficient -5, zeros at 9,2-8 i and 2 +8 i. O A. f(x)= - 5(x- 9)(x2 - 4x +68) OB. f(x) = -5(x +9)(x - 2 - 8i)(x - 2 +81) O c. f(x) = -5(x -9)(x - 2 - 8 i)(x - 2 + 8 i) OD. f(x) = - 5(x +9)(x2 - 4x+68)
Find a polynomial of the specified degree that satisfies the given conditions. Degree 4; zeros −3, 0, 1, 4; coefficient of x3 is 4
Form a polynomial f(x) with real coefficients having the given degree and zeros. Degree 5; zeros: - 7; - i; 6+ i Enter the polynomial. F(x) =a (Type an expression using x as the variable. Use integers or fractions for any numbers in the expression. Simplify your answer.)
Information is given about a polynomial f(x) whose coefficients are real numbers. Find the remaining zeros of f. 1.) Degree 4; zeros: i, −17+i 2.) Degree 3; zeros: −4, 7−i
* 5. Form a polynomial f(x) with real coefficients having the given degree and zeros. Degree: 3; zeros: -2 and 2i (a) f(x) = x + 2x² + 4x +8 (c) f(x) = x2 – 2x² + 4x – 8 (b) f(x)= x + 2x2 - 4x + 8 (d) f(x) = x3 – 2x2 - 4x - 8
Form a polynomial f(x) with real coefficients having the given degree and zeros. Degree 4; zeros: 1, multiplicity 2; 2i Enter the polynomial. f(x) = all (Type an expression using x as the variable. Use integers or fractions for any numbers in Its
3) Write a polynomial f(x) that meets the given conditions. Answers may vary. 3) Degree 2 polynomial with zeros 212 and -222 A) S(x) = x2 + 472x+8 B) f(x) = x2-8 9 S(x) = x² + 8 D) S(x) = x2-11/2x+8 4) Degree 3 polynomial with zeros 6, 21, and -2i A) S(x) => x3 + 6x2 + 4x + 24 f(x)= x2 - 6x2 + 4x - 24 B) /(x) = x2 - 6x2 - 4x + 24...