Here ,
m = 3.8 Kg
E = 2*10^5 N/C
a = 26 m/s^2
as Second law of motion
Fnet = ma
qE - mg = ma
q*2*10^5 = 3.8*(9.8 + 26)
q = 6.8 *10^-4 C
the charge on the bead is 6.8 *10^-4 C
Fnet = qE - m*g
m*a = q*E - m*g
==> q = m*(a+g)/E
= 3.8*10^-3*(26+9.8)/200000
= 6.8*10^-7 C
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