Using the reaction shown below, calculate the percent yield obtained by a student when reacting 5.0 g of 3-methoxysalicylic acid with 3.9 mL of iodomethane in the presence of 10.3 g of potassium carbonate and obtaining 4.5 g of product, 2,3-dimethoxymethyl benzoate. You should determine which of the three reactants is the limiting reagent and the theoretical yield first.
We are given, mass of 3-methoxysalicylic acid = 5.0 g , volume of iodomethane = 3.9 mL , potassium carbonate = 10.3 g , Actual mass of product 2,3-dimethoxymethyl benzoate = 4.5 g
Reaction –
3-methoxysalicylic acid + iodomethane + potassium carbonate ------> 2,3 dimethoxymethyl benzoate
Now we need to calculate the moles of each reactant
Mass of iodomethane = density * volume
= 2.28 g/ml * 3.9 mL
= 8.892 g
Moles of 3-methoxysalicylic acid = 5.0 g / 168.15 g.mol-1
= 0.0297 moles
Moles of iodomethane = 8.892 g / 141.94 g.mol-1
= 0.0626 moles
Mole of potassium carbonate = 10.3 g / 138.21 g.mol-1
= 0.0745 moles
Now we need to calculate the moles of 2,3-dimethoxymethyl benzoate from each reactant
From the above-balanced reaction, all have a mole ration of 1:1
So each mole of reactant is equal to the moles of the product.
So the lowest moles of 2,3-dimethoxymethyl benzoate is 0.0297 moles and it is from 3-methoxysalicylic acid since there is mole ratio between the 3-methoxysalicylic acid and 2,3-dimethoxymethyl benzoate is 1:1
So, the limiting reactant is 3-methoxysalicylic acid and
Moles of 2,3-dimethoxymethyl benzoate = 0.0297 moles
Mass of 2,3-dimethoxymethyl benzoate = 0.0297 moles * 196.20 g/mol
= 5.83 g
So, the theoretical mass of 2,3-dimethoxymethyl benzoate is 5.83 g
We know, Percent yield = actual mass / theoretical mass * 100 %
= 4.5 g / 5.83 g * 100 %
= 77.1 %
Using the reaction shown below, calculate the percent yield obtained by a student when reacting 5.0 g of 3-methoxysalicylic acid with 3.9 mL of iodomethane in the presence of 10.3 g of potassium carbonate and obtaining 4.5 g of product, 2,3-dimethoxymethy
Activity 10 How Much Product Will My Reaction Yield? 37 6. Carly the chemistry student performs an experiment with vinegar (active ingredient acetic acid, CH, COOH) and baking soda (NaHCO). Her professor asks her to place varying amounts of baking soda and vinegar into scalable plastic sandwich bags, quickly seal the bags, and observe the reaction. The balanced chemical equation for the reaction is given here. NaHCO, (aq) + CH,COOH(ag) - CO,(8) + H,O(l) + NaCH COO(ag) a) Use limiting...