The intensity of solar radiation reaching Mars averages about 580 W/m^2.
Assuming that Mars behaves like a blackbody, how much energy is absorbed per unit time. What is equilibrium temperature if all this energy is re-radiated back into space?
a)
radius of mars, r = 3.39*10^6 m
surface area of mars = 4*pi*r^2
= 4*pi*(3.39*10^6)^2
= 1.44*10^14 m^2
Enery obsorbed per seccond = Intensity*area
= 580*1.44*10^14
= 8.352*10^16 J <<<<<-------Answer
b)
Use stefan's law
Eergy emited by a body per unit area per unit
time,
I = sigma*T^4
T = (I/sigma)^(1/4)
= (580/(5.67*10^-8))^(1/4)
= 318 k <<<<<-------Answer
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