EXAMPLE 2 Find sin$(7x) cos”7x) dx. SOLUTION We could convert cos?(7x) to 1 - sin?(7x), but we would be left with an expression in terms of sin(7x) with no extra cos(7x) factor. Instead, we separate a single sine factor and rewrite the remaining sin" (7x) factor in terms of cos(7x): sin'(7x) cos”(7x) = (sinº(7x))2 cos(7x) sin(7x) = (1 - Cos?(7x))2 cos?(7x) sin(7x). in (7x) cos?(7x) and ich is which? Substituting u = cos(7x), we have du = -sin (3x) X...
Show detailed work 4. (9 points each) Integration: 77 1 Vx(1+x)2 sinx (b) S3 -dx (6-cos x) 3 (© 1.6.-2) )dx (d) St(t – 5)ºdt (e) 56x?=+*+VX-4 dx
9) Find ( 5x+3x+3x dx a) O 5x2 + x3 + x2 + c b) O 5x3 + 2x2 + 3x + c c) O 5x3 + 2.x + 3x + с d) 0 5x + x² + x3 + c 8) Find the most general solution of the differential equation dx C49602 Weight: 1 = 6x2 - 7; given that y = 5, dy = 2, when x = dx o. a) y = PR + 2x + 5...
Establish the identity. 1 - sec 0 1 + sec cos 0-1 cos + 1 1 Which of the following four statements shows the key steps in establishing the identity? ОА. 1 cos + 1 1 - 1 - sec 0 cos e cos Ꮎ cos 0-1 1 + sec 0 1 1 + cos 0-1 cos 0+1 cos o cos e B. 1 cos + 1 1 + 1 - sec 0 cos o cos Ꮎ cos 0-1 1...
1. Evaluate the indefinite integral sen (2x) – 7 cos(9x) – sec°(3x) dx = 2. Evaluate the indefinite integral | cor(3x) – sec(x) tant(x) + 9 tan(2x) dx = 3. Calculate the indefinite integral using the substitution rule | sec?0 tan*o do =
dx vx (x) = . | 0 Invalid input. Please enter a valid answer. dx (9x4 +15x9) dr a. fio (x) = 1 0 Invalid input. Please enter a valid answer. dx 3x +9 log (x) dx vx (x) = . | 0 Invalid input. Please enter a valid answer. dx (9x4 +15x9) dr a. fio (x) = 1 0 Invalid input. Please enter a valid answer. dx 3x +9 log (x)
Evaluate f(3x3 +Vx+ 2x-1 - 3x+2/3)dx
Solve the initial value problem. 1 dy y cos e Ꮎ dᎾ = y(O) = 1 y4 +1 The solution is (Type an implicit solution. Type an equation using and y as the variables.)
i need help evaluating each of the integrals! thank you in advance! n 9 10 11 12 13 14 15 t? f (2x® – 1)dx b) $\(5x – 7)da c) | 5e?* f(et)dx 0 d) f (5 sec(3x)) tan(3x) - dx cos(3x) (Vx :-1) dx 1 f (6sin(2x)) - dx sec(2x) 12
0 bie 3x2_1 e CX 3x)2 dx 2 esco cos va va dx 3 l sinx sec? (cosx) dx • 7/2 cosx sin (sinx) dx 10 s S; X=(1+2x9) "dx x2 sixe dx @[Cittam bjpecede 8 4+3x sin (lax)