A 30-kg solid sphere of radius 0.12 m is rolling without slipping on a horizontal surface...
A 30-kg solid sphere of radius 0.12 m is rolling without slipping on a horizontal surface at 1.7 m/s. What average torque is required to stop the sphere in 5.0 rev without inducing skidding?
Homework Answers
I =( 2/5) MR2 = 0.4 *30 *0.0144 = 0.173
Velocity = 1.7 m/s.
W = 1.7/0.12 = 14.17 rad/sec
Angle of rotation = 5*2pi = 10*3.14 = 31.4 radian
0 = 14.172 - 2*a*31.4
a = 3.2 rad/s2
Now Average torque = Ia = 0.173 * 3.2 = 5.53 Nm
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