Pplease show you work! I cannot figure out the steps
Let DC=10ft
BC=6ft
Let CE=b
AB=a
In triangle ABE and DCE
a/6+b=10/b
a=(60+10b)/b
Let AE=L
L^2= a^2 + (b+6)^2
=((60+10b)/b)^2 +(b+6)^2
Differentiate
2L dL/db= 2(60+10b)/b(-60/b^2)+2(b+6)
=-120(60+10b)/b^3+2(b+6)
dL/dB=0
0=2(b+6)(1-600/b^3)
b=-6
b=600^(1/3)=8.434
L^2=((60+10*8.434)/8.434)^2+(8.434+6)^2
=292.897+208.34035=501.23735
L=22.3883
Pplease show you work! I cannot figure out the steps A fence 10 ft high runs...
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