A titration is carried out to determine the concentration of the acid in an old bottle of aqueous HCl whose label has become unreadable.
What is the HCl concentration if 61.7 mL of 0.150 M NaOH is required to titrate a 20.0 mL sample of the acid?
The reaction is given as :
HCl + NaOH = NaCl + H2O
So by using the formula M1V1 = M2V2
where M is Molarity and V is the volume
By putting all the values we get :
0.150 x 61.7 = M2 x 20.0
M2 = 0.463 M
So the molarity of the acid will be 0.463 M
A titration is carried out to determine the concentration of the acid in an old bottle...
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