Question

1 2004 Hypothesis test for 1 mean Page 406-413 A fast food restaurant claims that the mean waiting time is less than 3.2 minutes (original claim). A random sample of 36 customers revealed a sample mean waiting time of 2.8 minutes with a sample standard deviation of 0.301 minutes. Test the restaurants claim at a a= 0.05 level of significance. Assume that the population has a normally distribution and the population standard deviation is unknown. Use the Traditional method to test the restaurant's claim Use the guidelines (with graph) and number each step. (Hint: Use t-test) 15 points total. graph is 4 points. 1 The

plz answer correctly with all the steps

Answer 1

Ans we have given. sample size (n)= 36, simple mean waiting time (T) = 2.8 min semple standard dev (s) - 0.301 min Slep-I Claim: mean wait time is less than 3.2 Ho. l = 32 Ho: ll 23.2 Cone failed) we will use t test because, pop. Standard der is unlenown slep-II the significance level is 220.05, the cashical value for a left tailed. test is ctc=-1.69. fiyet hos ل مطاط O slip-II :- et? -7973 - 2.8-3. 2 0.301/536 3155 that at = -7.973<t=-169 Ho is rejected pralue is less than step- since it is oheared = it is then concluded that the pralue =0.000, since 0.05 so we reject to step It we have sufficient the claim. evidence to accept