Question

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A vertical spring with spring stiffness constant 305 N m oscillates with an amplitude of 28.0 cm when 0.260 kg hangs from it. The mass passes through the equilibrium point (y=0) with positive velocity at t = 0. Assume that downward is the positive direction of motion. What equation describes this motion as a function of time? Express your answer in terms of t. % AED mo? y(t) - Submit Previous Answers Request Answer * Incorrect; Try Again; 2 attempts remaining Part B At what times will the spring be longest? O 4.59 . 10-25 4.59 . 10-3+n. (0.183 s), n 0 ,1,2,... 4.59.10-'8+1 (0.366 s), n = 0,1,2,... 9.18. 10-25 9.18.10-28+ (0.183 s), n 0 ,1,2,... 9.18.10-28+ (0.366 s), n = 0,1,2,...

Answer 1

An- (A) A Sin wt 28 Cm O.28m A= 305 R 11 O-260 34.25 rads ) yl) sin ot A E A Sin ot a sin lu) a/2 7/2 wt 34.25 xt -3 t 2 X34.25 t:0.0459 Sec t-4.59X1 Sec 3