Its given that,
Battery Voltage = Vb = 9 volts ; R1 = 15 Ohm and R2 = 23 Ohm ;
L = 0.46 Henry ; V(L) at t = 0.008 seconds
1/Req = 1/R1 + 1/R2 = 1/15 + 1/23
Req = 9.08 Ohm
time constant = L/R = 0.46 / 9.08 = 0.0506
we know that, Voltage across an inductor at time t is given by
V(L) = Vb e-tR/L
V(L) = 9 x e-0.008/0.0506
V(L) = 0.854 Volts
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I4(0)
... current through R4 just after switch is closed ... =
0.04196 A
I4(∞) ... current through
R4 after switch has been closed for a very long time ...
= 0.05539 A
IL(∞) ... current through inductor
after switch has been closed for a very long time ... =
0.03767 A
VL,max(closed) ... maximum voltage
across inductor during the time when switch is closed ... =
4.28 V
VL,max(open) ... maximum voltage
across inductor during the time when switch...
answer all
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B) Calculate the current through each resistor when the switch
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R1
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