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on 38 of 58 > Determine the OH). pH, and pOH of a solution with a [H+ of 0.038 M at 25 °C. [OH-] = 6.93 x10-13 M Incorrect p
Incorrect Determine the (H+). [OH-], and pOH of a solution with a pH of 9.13 at 25 °C. 7.41 x10-10 M [OH-] = 1.35 x10-5 M pOH
H*] = 7.41 x10-10 M (OH) = 1.35 x10-5 M pOH = 4.87 Determine the (H+). (OH), and pH of a solution with a pol of 12.08 at 25°
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Answer #1

Some important formulas regarding pH, pOH are in the solution uploaded below.

pH= -log[H+]

pOH= -log[OH-]

pH + pOH = 14 at 25°C

I water Н,01) гні-три гConj} ka) -log [н] [ht] = 10 PH Kwa disocation const out pot = log Гон) kira (4+] [or] [н]: kus [ou]

3 . = 12:08 рон [он] = Брон 10.02 2-8- 3 1 xjo 13 [++] = kw Гон I only 8-317x10:13 - 0:0 12 - 14- 1908 Р - в 19- рон - 1-92

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