Question

(24) Consider the water heat distribution system shown below where: i) The fractions refer to the fraction of the stream flowing, e.g. 30% of the stream leaving the 75,000 Btu/hr heater goes to the exit iQis a heater, energy being added to the water stream Water 1500 lb/hr T 60°F 0.3 75,000 Btu/hr 0.7 -30,000 Btu/hr -50,000 Btu/hr 0.9 0.1 200,000 Btu/hr a) What is the outlet temperature and quality (mass fraction steam)?

Answer 1

Solution mP wate 7s000 Btu/h O.3 9 Bty -Soooo -30 00o 12600. O-1 ttr Now hole Syfem Ouenau fhe balan c On ( Total mas ou eut To tal Input ISoo So o Since O. 3 m m3 o.3 Soao

Also (0058= Sw O.7 m :hw 3500 Also n Zw 350 O. g ms 씨7 mg 31SO mg Also D OSE make enthaspy balono a min Reftenca tempoatun dinst Point we So TR = A rig CTg-T r and tate Cp Commm Can mg Tg - Tre - meTF -(mptms TR = mg Ts -mT &inu myTH mp Tp

Po nd Bolonces de imilar make Now qnod also also sinply fy Abore balane 3500 Tg Soo o so00 Tt Gooo o 3sOO Tg waten heaten sooo B enthaley balanu Now m,Cr CT2T) +5000 T2-) Sooo balana at aiaeput rn enthaley No w the's ginca &plitiry Same rem acosf Ty T3 aroun -5000O Endholpy Calane (-^)h 3s00 TTy) 4.28S TsTy

T2 Tu T2 dame stream Sout trom Shreom ( and Ts- T6 = Noco 2000 00 enthalpy balanco Ta - T 3500 T- Ta = 57J,428 4) at mixiny pont balana enthaley Noco ma Ta m T t 3150 T 350 Ta 3So oT (4-2 Bfu heatr batana Now enthopy 8.S71 Tg T3

om equotnO T2 Is Nous Rud - Ao in equatia fom eguia, Rut T2 4.2gs +T Also Ts Tg Prom egu hits 8 eguah'sn become (T2-15 Sooo 3so0 CTg- 35H4) Saooo goooo 350 o T 30000 C4235Ts) 350 o TB a (3S00 0 SOoo T -3T00 Tg RI425 35000 63573 Sooo Ts 8olue equa Nou we S9ltSt 747. I4 232.83 drom uin Now + SL = u 4.285 Temperotu outtest T3 Quakthy Liguid wafen