Question

1. ESRB Ratings ─ Pseudocode

The following rules are a modified version of the rules used to describe how to categorize video games into one of four Entertainment Software Rating Board (ESRB) categories – Mature (M). Teen (T), Everyone (E), Unknown (U).

1. If the game has intense violence or sexual content, then it should be rated Mature.
2. If the game has some violence or some strong language, then it should be rated Teen.
3. If the game has mild content, then it should be rated Everyone.
4. Otherwise, if the game does not fit into any of the above categories, then it should be rated Unknown.

Provide a pseudocode algorithm that uses this categorization scheme to determine the rating for a particular video game. More specifically, read in (1) the name of the video game, and (2) characteristics as needed (like whether the game has intense violence or sexual content, etc.) that help to determine which rating to assign to the game. Then print the game’s name and its rating.

Hint: Use a series of nested “if, else” statements. Inside each else section, prompt for an additional characteristic and then start the next “if, else” statement inside the previous else section. Remember that each “else” must be aligned with its partner “if” (as opposed to putting the else all the way at the left column). To determine a game’s rating, use this code as a starting point:

print “Intense violence or sexual content? (y/n): ”

input mature

if mature equals “y”

print gameName + “ rating: Mature (M)”

else

print “Some violence or some strong language? (y/n): ”

input teen

if teen equals “y”

…

Answer 1

Thanks for the question.

Below is the pseduocode you will be needing  

Thank You !!

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print ('Does the game has intense violence or sexual content (y/n)? ')
input intense

if intense equals'y'{
print(gameName +' Rating: Mature (M)')
}
else {

print ('Does the game has some violence or some strong language (y/n)? ')
input teen
if teen equals'y'{
print((gameName + ' Rating: Teen (T)')
}
else{

print('Does the game has mild contence (y/n)? ')
input everyone
if everyone equals'y' {
print((gameName + ' Rating: Everyone (E)')
}
else{
print(gameName + 'Rating: Unknown (U)')
}
}
}