Question

17.6 Based on the information in Appendix D, calculate the pH and trimethylammonium ion concentration of a solution of trimethylamine, (CH3) 3N, 0.075 M, and trimethylammonium chloride, (CH3) 3NHCl, 0.10 M.

CONSTANTS OF AQUEOUS BALANCE Кок LO X 107 3.0 X 10-12 X L6 X 10 12 Kat 18 X 105 5.6 X 10- 5.1 X 10-10 3 X 10 6.3 X 105 5.8 X 10 10 15 X Ls 43 X 10 14 X 1st 1 x 102 74 X 10 35 X 10 L 8 X 10 1.9 X 10" 49 X 10 10 5.6 X 0-1 .7 X 10 4 .0 X 10 TABLE D.1 Dissociation constants for acids at 25 C Name Formula Acetic acid CH, COOH for HC, H, 0) Arsenic acid H, ASO Arsenious acid HyAso Ascorbic acid H, C, H, O, Benzoic acid Boric acid H, BO, Butanoic acid C. HCOOH (or HC, HO.) Carbonic acid HCO, Chloroacetic acid CH, CICOOH (or HC, H, O, CH) Chlorous acid Hao Citric acid HOOCC (OH) (CH-COOH): (or H, CH, O) Cyanic acid HCNO Formic acid HCOOH (or HCHO:) Hydrazoic acid HN. Hydrocyanic acid HCN Hydrochloric acid НЕ Ion hydrogen chromate HCTO Hydrogen peroxide HO. lon hydrogen selenate HSe04 Hydrogen sulfide HS Hypobromous acid HBrO Hypochlorous acid HCIO Hypoiodic acid HIO lodic acid HIO. Lactic acid CH, CH (OH) COOH (or HC, H, 0. Malonic acid CH, (COOH): (or H; CH, O.) Nitrous acid ΗΝΟ, Oxalic acid (COOH): (or H; C: 0.) Paraperiodic acid H, 10, Phenol C, H, OH (or HCH, O) Phosphoric acid H. PO Propionic acid C, H, COOH (or HC, H, 0.) Pyrophosphoric acid H. P. 0, Selenious acid H SeOy Sulfuric acid H, SO Sulfurous acid H, SO Tartaric acid HOOC (CHOH), COOH (or HC, H, O) IX 10 19 20 X 15% 2.0 X 10 2.4 X 102 22 X 10 9.5 X 106 2.5 X 10 3.0 X 10 2.3 X 101 1.7 X 10 14 X lo 1.5 X 10 4.5 X 10 5.9 X 102 2.8 X 102 1.3 X 10 10 75 X 10 -> 1.3 X 105 3.0 X 102 23 X 10 Strong acid 1.7 X 102 1.0 X 10 6.4 X 103 5.3 X 109 6.2 X 10 4.2 X 1013 2.1 X 10 4.4 X 103 5.3 X 1-9 1.2 x 102 64 X 10 - 1062

Answer 1

According to the condition given in question We have (CH3), N = PKD =4.19 pot = pkb + log [sait] Salt = (CH3)3 NHCR = 0.10 M Base = 0.075 M. pot = 4.19 + 40g (2015) pot = 4.19 0.075 pol = 4.318 pH = 14-pott pH = 14 – 4318 pH = 19.68 )

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