Question

please explain andsolve



cTOIIs On the N atom. PCI3(g) + Cl2(g) 근 PCIs(g) K.-6.5 36. At a certain point in time, a 1.00L rigid reaction vessel contain
0 0
Add a comment Improve this question Transcribed image text
Request Professional Answer

Request Answer!

We need at least 10 more requests to produce the answer.

0 / 10 have requested this problem solution

The more requests, the faster the answer.

Request! (Login Required)


All students who have requested the answer will be notified once they are available.
Know the answer?
Add Answer to:
please explain andsolve cTOIIs On the N atom. PCI3(g) + Cl2(g) 근 PCIs(g) K.-6.5 36. At...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Similar Homework Help Questions
  • 9.3 Consider the gas phase reaction: PCI3(g) Cl2(g) PCI5(g) at equilibrium at 400 K and 1...

    9.3 Consider the gas phase reaction: PCI3(g) Cl2(g) PCI5(g) at equilibrium at 400 K and 1 atm total pressure. The closed system is initially charged with 1 mole of PCI3 and 2 moles of Cl2 The standard free energy change of this reaction is -3.53 kJ/mole. What is the mole fraction of PCI5 at equilibrium?

  • The equilibrium constant Kp for the reaction CC, (g) 근 C(s) + 2 Cl2 (g) at...

    The equilibrium constant Kp for the reaction CC, (g) 근 C(s) + 2 Cl2 (g) at 700°C is 0.73. Determine the initial pressure of carbon tetrachloride that will produce a total equilibrium pressure of 2.60 atm at 700c. Pressure- atm Try Another Version 4 item attempts remaining At a particular temperature, K = 2.0 × 10-6 for the reaction 2 CO (g) + O2 (g) 2 CO2 (g) If 2.5 moles of CO2 is initially placed into a 5.0-L vessel,...

  • Consider the following reaction where K. = 83.3 at 500 K: PC13(g) + Cl2(g) = PC15(8)...

    Consider the following reaction where K. = 83.3 at 500 K: PC13(g) + Cl2(g) = PC15(8) A reaction mixture was found to contain 2.76x10-2 moles of PC13(g), 4.46x10-2 moles of Cl2(g) and 0.133 moles of PC13(g), in a 1.00 Liter container. Indicate True (T) or False (F) for each of the following: (- 1. In order to reach equilibrium PC15(g) must be consumed. 2. In order to reach equilibrium K, must increase. 3. In order to reach equilibrium PC1z must...

  • At 390 K, the equilibrium constant, Kc, for the reaction below is 1.8 × 10–3. 1....

    At 390 K, the equilibrium constant, Kc, for the reaction below is 1.8 × 10–3. 1. PCl5 (g) ⇔ PCl3 (g) + Cl2 (g) Assume a quantity of PCl5 (g) is placed in a rigid 10 L vessel and the system is allowed to reach equilibrium at a constant temperature of 390 K. Identify whether each of the following statements is true or false. a) At equilibrium, if the vessel contains 1 mole of PCl5 (g)it must contain 0.0428 mol...

  • Thank you Question 5: (1 point) At 390 K, the equilibrium constant, K., for the reaction...

    Thank you Question 5: (1 point) At 390 K, the equilibrium constant, K., for the reaction below is 1.8 x 10-?. PCIs (g) - PC1; (g) + Cl2 (g) Assume a quantity of PCIs (g) is placed in a rigid 10 L vessel and the system is allowed to reach equilibrium at a constant temperature of 390 K. Identify whether each of the following statements is true or false. At equilibrium, if the vessel contains I mole of PCs (g)...

  • 1. For the following balance: 2 HF (g) H2 (g) + F2 (g) 73Kcal Indicate what...

    1. For the following balance: 2 HF (g) H2 (g) + F2 (g) 73Kcal Indicate what will happen with each of the following changes: a) Decrease in HF concentratiorn b) Increase in temperature c) Decrease in pressure d) Increase in H2 concentration ej Increase in the concentration of F2 2. At 130 oc the sodium bicarbonate, NaHCO3, decomposes partially according to the following equilibrium: 2 NaHCO3 (s) sNa2CO3 (s) + CO2 (g)+ H20 (g) Ko= 6.25. 100 g of NaHCO3...

  • (a) For the reaction 2NO2 (g) 2NO (g) + 02 (g) K # 0.50. Predict the...

    (a) For the reaction 2NO2 (g) 2NO (g) + 02 (g) K # 0.50. Predict the direction in which the system will move to reach equilibrium if the initial gas pressures are NO: 0.20 atm . NO2: 0.20 atm (answer: to the right because Q< K) .NO2: 0.0961 atm 02: 0.0589 atm NO: 0.280 atm (answer: the system is already at equilibrium because Q -K) O2: 0.20 atm NO: 0.56 atm NO2: 0.20 atm (answer: to the left because Q>...

  • The general form of a chemical reaction is aA + bB = cC +dD Where A...

    The general form of a chemical reaction is aA + bB = cC +dD Where A and B are reactants in the forward direction and C and D are products in the forward direction. The lower case letters are the stoichiometric coefficients for the balanced equation. The general form of the equilibrium constant equation is then: Keq = [C]c[D]d/[A]a[B]b Part I: Q vs. K Q: reaction quotient can be calculated for a reaction at any concentration values of reactants and...

  • please answer all. thank u Equm U ving reaction for Questions 1 - 3 and answer the questions based upon th sed upon...

    please answer all. thank u Equm U ving reaction for Questions 1 - 3 and answer the questions based upon th sed upon this Consider the following reaction reaction: co (g) + 3 H, (g) + CH (9) + H2O (g) 1. At 25°C. Kega 4.0. What must be Kes 4.0. What must be the coat equilibrium If the rulibrium concentrations on HJE 2.0M, (CH) = 5.OM, and [HO] - 3.OM? Answer: 0.469 M a way to keep track of...

  • with explanations thanks A4 The molecular dipole vector is the sum of bond polarities and indicates the direction and...

    with explanations thanks A4 The molecular dipole vector is the sum of bond polarities and indicates the direction and extent of polarity on a molecule, the vector arrow points from the net negative domain towards the net positive domain. Identify which ONE of the following molecules has the molecule polarity correctly indicated by the dipole vector H H H H H H H H H H H (A) (B) (C) H H H H H (D) (E) A8 When a...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT