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A variable is normally distributed with mean 23 and standard deviation 5. Use your graphing calculator to find each of the fo
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Page No. Ans. Date Given that, mean = M = 23 standard deviation=6=5 I P(x < 26) - Plx-u < 26-23) 5 Plz <0.6) 30.7258 Ut b) p(c) P(x>25) - - P(x525) - - Pld- ll . 25-23 II - P(Z < 0.4) = 0.3446 a P(x > 29 = - Pla529) - 1-P (x-M 29-23) o 5 e -plza 1.2)Page No. Date P(17<x<30) = P(x230) - P(x517) = P(2530-23) - P(Z < 17-23) = P(za 1.4) - Plec-1-2) = 0.9192 - 0.1151 - 0. 8041

0.2 ਗਤ : 2 : ::: 43:32 33 325 ਈ. ੨੧ ੨ ੩ ॥ ੧ ॥ STANDARD NORMAL DISTRIBUTION: Table Values Represent AREA to the LEFT of the Z-3.7 -3.6 -3.5 -3.4 -3.1 -2.9 STANDARD NORMAL DISTRIBUTION: Table Values Represent AREA to the LEFT of the Z score. .00 .01 .

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