Homework Answers
Reaction:-
Zn + Fe2+ -> Fe + Zn2+
Half cell rxn.:-
Cathode (Reduction):-
Fe2+ + 2e -> Fe
Anode(Oxidation):-
Zn -> Zn2+ + 2e
E°cell=E (Fe2+||Fe) -E (Zn2+||Zn)
=0.44 -(-0.76)=1.2volts
Hence,E°cell=1.2volts
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