Question

Questions Provide concise answers (couple of sentences) to each of following questions using complete sentences and referring to the data collected. Questions 1 and 3 ask you to show your work in calculating buoyancy and stability values for select objects. You still need to do these calculations for the other objects and enter the results in the tables above. Experiment 1- Buoyant force on submerged objects 1. Show an example calculation for how you determined the buoyant forces for the aluminum object. 2. Compare the buoyant forces among the three objects. Why do they differ? Experiment 2 - Stability of floating objects 3. Show example calculations for the area moment of inertia (1..), metacentric height (GM), and tipping moment for the wood object for both the short or long axes. 4. What happened to the waterline shape as the object was loaded? Did it change? 5. Qualitatively describe the observed differences in tipping moments along short and long axis in terms of the mathematical description of stability. Can you extend this idea to real floating objects? For example, is a ship more likely to tip over to the side, or end-to-end? Extra Credit (up to 5 points] Write a brief description (complete sentences), and include relevant equations, of how one can determine the specific weight (Yobject) of a floating object using only a ruler and the known properties of water (y,p). |

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Answer 1

Solution of the given experiment are shown below

QUESTION'S EXPERIMENT -1 OLUTION-1 + ARCHIMEDES PRINCIPLE states that the abiect immercia buoyant fouce acting on an object in a fluid is equal to the con of fluid displaced. Generally the buyent fonce is a result of Prenure exerfed by fluid. Generally alluminium ball is sink in Water Liquid Sweface Let us take object is immersed in Liquid. A = Area of Sweface G= Centroid of Sweface ž= Depth from Liquid Surface W = spécific weight Total Prenare force on object is - Specific Weight: X Volume = specific weight & Aroa of Surface x depth - W4x

SOLUTION-2- Comparison of buyont force among three ION-2 objects. WOOD Wood is float because be greater cause buyont force is than the object weight density and also is lighter than the water so wood floats. Metal Metal link's became weight is greator than the fluid it displace's also it's doncity is denser than the fluid it displace's. Floating balloon - It's weight is equal to the flacid it displaces Generally this are Galled Neutral busyonary. EXPERIMENT - 2 - SOLUTION 3. P iW BAP Metacentele is the Centee through which when a floating body given a small angular displacement it's start oscillating about that centul ... Figure show's floating body- = centre of Guarity B = centre of Buyoncy

on lyM is meta centric height force of Buayancy on given by element small Upward is a SP=W.SV = W.R.G. SA where we Unit weight of liquid Moment of this buyoncy force abouto is & SPB = Wx²O SA Total Moment is SxdPo=fwQx²dA Sad Po= wo Sada due = wo. I Where I is moment of inertia . of Sectional weea Now fx.der giver chang in Moment to kvojancy Se dla = PBA BB Now BB = BMXQ and PB = 2D XV. So, we get w.o. I = W.V.BM.O. or BM = -2 Now Metacentriç height GM - BM I Bly the sign : - ve sign! Gist lower than B Gis higher than B.

SOLUTION-4- When object was loaded. A known Weight w, is shifted by a distance z acuan the ani's of Hit. The Change in Moment is equal to W.GG, or WGM tano W, z = Waltro GM = WZ W. tono