An ideal gas at 20 ∘C consists of 2.2×1022 atoms. 9.0 J of thermal energy are...

Question

Question

An ideal gas at 20 ∘C consists of 2.2×1022 atoms. 9.0 J of thermal energy are removed from the gas. What is the new temperature in Celsius?

Answer 1

Answer #1

as we know from the expression of thermal energy

E = (3/2)N k ( t2 - t1)

9 = 1.5 * 2.2 * 10^22* 1.38* 10^-23 * ( 20 - t2)

t2 = 0.237 C

=====

Answer 2

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