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(ii) Our swapped system now looks like: -6x+3y7 3 2y 3 Lets say you now wanted to solve this new swapped system of equations by multiplying the bottom equation by 2 and adding it to the top equation to eliminate the r to solve for y. We can do this in the matrix equation as well. Rewrite the swapped matrix equation so that it represents what happens when you take 2 times the bottom equation, add it to the top equation, and insert the result in the bottom row of the matrix equation. Also give the matrix, M which performs this operation. Again, make sure to multiply both sides of the equaion by this M matrix. ii) Finally, in order to solve for y all we have to do is divide the matrix equation by whatever value remains in the lower right-hand side of the matrix. Once we scale the equation by this value then we can directly see what y is equal to if we multiply the [x, y]? vector through. This solving process is known as back-substitution. Give the final value of y and r.

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