Ans:
Use binomial distribution with n=15 and p=0.80
P(x=k)=15Ck*0.80k*(1-0.80)15-k
a)
P(x=4)=15C4*0.804*(1-0.80)11=0.00001
b)
P(all)=P(x=15)=0.8015=0.0352
c)
P(x<3)=P(x=0)+P(x=1)+P(x=2)
=0.0000+0.0000+0.0000
=0.0000
d)
Expected number=15*0.8=12
standard deviation=sqrt(15*0.8*0.2)=1.55
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