You are trying to overhear a most interesting conversation, but from your distance of 10.0m , it sounds like only an average whisper of 20.0dB . So you decide to move closer to give the conversation a sound level of 60.0dB instead. How close should you come?
Part E
When you decide to move closer, to a distance r2 from the source, to give the conversation a sound level of 60.0dB, how close should you come?
Express your answer in meters to three significant figures.
You are trying to overhear a most interesting conversation, but from your distance of 10.0m ,...
You are trying to overhear a juicy conversation, but from your distance of 18.0m , it sounds like only an average whisper of 40.0dB . So you decide to move closer to give the conversation a sound level of 70.0dB instead. How close should you come? __ cm
You are trying to overhear a juicy conversation, but from your distance of 20.0 m, it sounds like only an average whisper of 25.0 dB. So you decide to move closer to give the conversation a sound level of 65.0 dB instead. How close should you come? Express your answer in centimeters.
You are trying to overhear a juicy conversation, but from your distance of 18.0 m, it sounds like only an average whisper of 30.0 dB. So you decide to move closer to give the conversation a sound level of 75.0 dB instead. How close should you come? Express your answer in centimeters.
(1 point) You are trying to overhear a juicy conversation, but from your distance of 30 m, it sounds like only an average whisper of 10 dB. You decide to move closer so that the intensity level increases to 60 dB. How close would you have to be in order to hear this intensity level? (Note that the answer might be uncomfortably close.) Distance =
What intensity I1 corresponds to 20.0 dB ? Express your answer in watts per square meter. You are trying to overhear a most interesting conversation, but from your distance of 10.0 m , it sounds like only an average whisper of 20.0 dB . So you decide to move closer to give the conversation a sound level of 60.0 dB instead. How close should you come? View Available Hint(s) IVALO ? 11 = 9.9 W/m² Submit Previous Answers X Incorrect;...
You overhear the following conversation Ty: “We created a diffraction pattern on the distant screen by illuminating a pair of long narrow slits with green light. The next instruction wants us to make the bright fringes of the diffraction envelope expand away from the center. I think we should find a different laser to do this – a red one would work well.” Sarah: “No, we shouldn’t use a different laser, we should just move the screen we’re making the...
You overhear a conversation between Mark and Anne in the gym. Mark is saying that he can bench press on average 200 pounds. Anne responds that on average she can bench press more. Mark then challenges her, saying "Show it!" Apparently, Anne keeps track of her data well, because she answers: "In the last n = 45 times, I pressed y = 205 with s2 = 24.5 pounds." She then suddenly turns around, looks at you, and says: "You are...
Your friend is belching the alphabet. Where you are standing, a distance of 2 meters from your friend, the peak sound level of their belching is 68.2 dB. You would like to move far enough away from them that you won’t have to hear their belching. Assuming that the belch noises approximate spherical waves, how far should you stand from your friend in order for the peak intensity of the sound to be the threshold of hearing, 10^−12 W/m2?
You sit a short distance from your speaker system, and the sound level is 21.6 dB You then get up and move to a spot twice as far away. What is the sound level at this new position ?
9. The scanning-tunneling microscope works on the principle of electron tunneling. Imagine you are trying to optimize your scanning tunneling microscope. Your microscope has a gold tip (work function 5.1 eV) and your electron has a kinetic energy of 4.6 eV (a) If you move the tip to sample distance from 0.3 nm to 0.2nm how does the transmission probability change? (b) You have a "brilliant" idea. What if you use protons instead of electrons? How will the transmission probability...