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A 0.20 kg ball is thrown straight up into the air with an initial speed of 17 m/s. Find the momentum of the ball at the following locations. (a) at its maximum height kg-m/s (b) halfway to its maximum height kg-m/s
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Answer #1

PA= 020 (17)2 = 2(+9.8) H H= 14.745m h 14.745737 m 2- 2. 22-07)2 - 2 (-9.8)737) gn-12.02m/s 12ml,8

Momentum at half the height = 0.20(12) = 2.4 kgm/s

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