Solution :
A) Solubility of Copper(II) hydroxide:
Addition of HBr increases the solubility of Cu(OH)2 because it forms highly soluble CuBr2.
Cu(OH)2 + 2HBr === CuBr2 + 2H2O
B) Solubility of Zinc carbonate (ZnCO3):
Addition of HBr increases the solubility of ZnCO3 in water because ZnCO3 is basic carbonate. Hence, addition of HBr shifted equilibrium towards forward direction.
ZnCO3 + 2HBr ==== ZnBr2 + H2O + CO2
C) Solubility of Lead bromide:
Addition of HBr decreases the solubility due to common ion effect. Bromide ion is common for both PbBr2 and HBr. The addition of HBr causes a decrease in ionization of PbBr2.
PbBr2. = Pb2+ + 2Br-
HBr == H+ + Br-
Due to common ion effect, solubility decreases.
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