Question

Marketing companies are interested in knowing the population percent of women who make the majority of household purchasing decisions.

Suppose a marketing company did do a survey. They randomly surveyed 200 households and found that in 120 of them, the woman made the majority of the purchasing decisions. We are interested in the population proportion of households where women make the majority of the purchasing decisions.

Which distribution should you use for the problem? ( Round your answers to two decimal places)

Answer 1

Answer: Here we use normal distribution

The proportion of households where women make the majority of the purchasing decisions is

120 p 0.6

$\widehat{p}$ is normally distributed with a mean of

lip 06

and the standard deviation is

op-0.6*0.4/200 0.0346

as long as np and n(1-p) are greater than 10

Answer: N(0.6,0.03)