1. A circular secondary clarifier (a.k.a. a final clarifier) is to be designed for an activated...
A wastewater treatment plant that treats wastewater to secondary treatment standards uses a primary sedimentation process followed by conventional activated sludge process composed of covered aeration tanks and secondary clarifiers. You are asked to calculate the different operation parameters to make sure that the system is operated within normal process ranges listed in the reference tables below. Table 5-20 Typical design information for primary sedimentation tanks U.S. customary units Item Unit Range Typical Primary sedimentation tanks followed by secondary treatment...
Secondary Treatment Based on a plant flow rate of 40 mgd, design an activated sludge, secondary treatment system with recycle which maintains a MLVSS = 2,000 mg/L in the aeration reactor and has an average Solids Retention Time (SRT)-4 days. The biota kinetic constants are Kinetic Coefficients for the Activated-sludge Process for the Removal of Organic Matter from Domestic Wastewater Endogenous Decay Coefficient- k(d) 0.1 Half-velocity constant- K(s VSS/qVss-da 15 Mg/L bsCOD Max. Specific Substrate Utilization Rate-k 6 G bsCOD/gVSS-da...
(30 points) A completely mixed activated sludge system comprised of an aerated reactor and a secondary clarifier with sludge return is going to treat 15,000 m/d of industrial wastewater. The primary effluent going to the reactor has a BODs of 1,100 mg/L that must be reduced to 150 mg/L prior to discharge to a municipal sewer. The pilot study was conducted and generated the following results: 3. Mean cell residence time- 5 day, MLSS concentration in the reactor 7.200 mg/L...
An activated sludge (AS) process is designed to treat 6000 people with a per capita contribution of 0.17 lb BOD5/ cap-day. The AS process receives flow from a primary clarifier with a BOD5 removal efficiency of 33%. The allowable solids loading rate is 40 lb BOD5/day per 1000 cubic feet of aeration basin. Determine the following: a) Aeration basin volume (cubic feet) b) Diameter of circular clarifier with a side-water depth of 10 feet.
Use the following data to size (volume in gallons) an activated sludge reactor basin (CFSTR with recycle and Monod) MLSS = 3500 mg/l MLVSS = 80% Yield Coeffiecient = 0.6 MLVSS BOD5 influent to the activated sludge basin = 230 mg/l BOD5 effluent to the activated sludge basin = 50 mg/l MCRT is 6 days Endogenous decay coefficient is 0.06d^-1 flow rate = 7 MGD
Given: There is a wastewater treatment plant that has a Primary Clarifier, Activated Sludge, Secondary clarifier and the average daily flow was 1 mgd. Calculate the volume needed if the activated sludge is 24 hours 10 Mgal 100 Mgal 1 Mgal 1000 Mgal
Environmental Engineering 3&4 So 3. An activated sludge plant treats 5 MGD and the average influent BOD is 200 mg/L. The WWTP has 2 aeration basins, each 100 ft x 25 ft x 15 ft deep and 2 final clarifiers with diameters of 20 ft. About 35% of BOD is removed in primary clarifiers. Determine the BOD in the primary effluent, hydraulic retention time, F/M ratio, BOD exiting the aeration basin and mass of solids wasted (1b/d). The operation parameters...
A wastewater flow of 18,000 m3/day is to be treated in a completely mixed activated sludge system at a concentration of 3000 mg/L MLSS (mixed liquor suspended solids). The secondary clarifier is designed to thicken the sludge to 12,000 mg/L. Assuming a growth yield coefficient of 0.5 Kg/Kg, an influent BOD of 100 mg/L with a residence time of 8 days, determine the following: a) The volume of the reactor b) The mass of the solids and the wet volume...
primary clarifier is to be designed for a municipal wastewater treatment plant with a flow of 4160 m/d and peak flow during the day of 3.10 times the average hourly flow. Pertinent data are: peak overflow rate 73.3 m/d.-m2, maximum peak weir loading 373 m3/d-m, and minimum tank depth 2.13 m. Determine: A. The clarifier diameter B. The side water deptlh C. The peak weir loading. Is it acceptable? D. The percent suspended solids removal on the basis of the...
Problem 7) Determine the recommended size of a new circular secondary clarifier for an activated-sludge system with a design flow of 26,000 m3 /d with a peak hourly flow of 32,000 m3 /d. Use maximum overflow rates of 33 m3 /m2 /day at design monthly flow and 66 m3 /m2 /day at peak hourly flow. The minimum side water depth is 10 ft (3.1 m), 11 ft for a 50-ft diameter tank, and 12 ft for 100-ft diameter tank or...