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8-1 A 15 kg block is dragged over a rough, horizontal surface by an applied 5 pts force of 71.9 N acting at 20.0 degrees abov

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Answer #1

a)

WF = Fd = 71.9* 5 cos 20 = 337.82 J

b)

N = mg cos x = 15* 9.8 cos 90 = 0 J

c)

Wg = - mg cos 90 = 0 J

d)

Wf = - u d ( mg - F sin x) = - 0.3* 5* ( 15* 9.8 - 71.9 sin 20)

Wf = - 183.61 N

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