Question

Q4. Helicopter P= 4000 lb is hanging in the air (in equilibrium). Assume that the lift F=0.04 P. Determine d, the distance between the axis of the main propeller and centre of gravity for the craft and the lift force F2. Use L=15 ft. Answers must be given in four significant figures and appropriate unit. State all the assumptions made in the problem solving. (PC: 3.1, 3.2, 3.3, 4.1), Range Statement (2),S1, S3-S6, S8-511, K1.1-K1.2. K10, K11-K19, K21-22 F, P d Resnonce:

Answer 1

Helicopter weight P = 4000 lb lift Fi = 0.04 P Fi = 0.04 X4000 160 lb L = 1567 >> d= ? F2 = ? Free Body diagram q I B A for equilibrium Condition w e Fitf =W = F2 = W-Fi - 4000 -160 F = 3840 lb for equilbrium Condition E Efyzo Efco EM=o taking moment about point B Fil= wd d = Fil/w 160 X 15 4000 d -0.6 ft

Here P and W are same in the answer.

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