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Take F = 290 N and d = 1,0 m. (Figure 1) Part A Determine the force in cable AC needed to hold the 23-kg ball Din equilibrium
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Answer #1

1.5m > F= 2900 Jo = 23kg Dº = tan = = 26.56 Xa tan 2os = 51.34 Resolving force 1. ↑ FCA Sn26.56. : 20.5 FCÀ Cas 26.56 -> F-Also we know, Efx=0 FBA sim $51:34) + FACi sin 26.56-225.630 0.78FBA +0.447 FAC =225.63 putting value of FB in above equation

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