Round your answers to two decimal places.
a. Using the following equation:
\(S_{\hat{y}},=s \sqrt{\frac{1}{n}+\frac{\left(x^{*}-\bar{x}\right)^{2}}{\sum\left(x_{i}-\bar{x}\right)^{2}}}\) Estimate the standard deviation of \(\hat{y}^{*}\) when \(x=3 .\)
b. Using the following expression:
\(\hat{y} * \pm t_{\alpha / 2} s_{\hat{y}}\)
Develop a \(95 \%\) confidence interval for the expected value of \(y\) when \(x=3\). to
c. Using the following equation:
$$ s_{\text {pred }}=s \sqrt{1+\frac{1}{n}+\frac{\left(x^{*}-\bar{x}\right)^{2}}{\sum\left(x_{i}-\bar{x}\right)^{2}}} $$
Estimate the standard deviation of an individual value of \(y\) when \(x=3\).
d. Using the following expression:
\(\hat{y}^{*} \pm t_{\alpha / 2} s_{\text {pred }}\)
Develop a \(95 \%\) prediction interval for \(y\) when \(x=3\).
to
a)
std error of confidence interval = | s*√(1/n+(x0-x̅)2/Sxx)= | 0.8287~ 0.83 |
b)
for 95 % confidence and 3degree of freedom critical t= | 3.1820 | |||||
95% confidence interval =xo -/+ t*standard error= | (5.96,11.24) |
c)
std error of prediction interval=s*√(1+1/n+(x0-x̅)2/Sxx)= | 2.0298~ 2.03 |
d)
for 95 % confidence and -2degree of freedom critical t= | 3.1820 | |||||
95% prediction interval =xo -/+ t*standard error= | (2.14,15.06) |
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