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O EXPONENTIAL AND LOGARITHMIC FUNCTIONS Finding the time to reach a limit in a word problem on... Savanah A laptop computer i
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Answer:

Data given:

Purchasing cost of the laptop computer, P = $3000

Each year, its value is 70% of its value the year before.

Number of years it will take for the laptop to be worth $600 or less = ?

Based on the given information, we can say that the given problem can be modeled using a decaying exponential function as -

Cost \ of \ the \ laptop \ after \ t \ years, \ C(t) = P(0.7)^{t} = 3000(0.7)^{t}

where P - purchasing cost of the laptop computer i.e. cost at time t = 0

Using the above function, we can find the number of years it will take for the laptop to be worth $600 or less as -

C(t) \leq 600

3000(0.7)^{t} \leq 600

(0.7)^{t} \leq 0.2

t \geq \log_{0.7}0.2

t \geq \frac{\log_{10}0.2}{\log_{10}0.7}(From \ logarithm \ property: \ \ \ \log_{a}b = \frac{\log b}{\log a} \ )

t \geq 4.512

Thus, the number of years it will take for the laptop to be worth $600 or less is approximately 5 years.

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