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The given State of Stress is provided, the stresses are as follows: • ox= 15 KSI oy= 10 KSI • txy = 8 KSI Part 1 - For the st

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givel, Ox = 15ksi oy= loksi Txya oksi e poles are = (159-8) (109+8) part- 1 For the state of stress described above or A Mohprinciple stresses - Let principle stresses are op, and op2- PP2 / 8P2 = 12.5 IR OP2= 12:5+ R - 12.5 + 8.3815 Py = 20.8815 Keh Maximum shear stress (Absolute):-([max) = - Imax +R = 8.3815kei In Absolute. (098.3815) Tmae, abs 6,75) Cocinplane Tmax) paAnd, ces = C0247.353°- CẢ - 8:3815 OA (OA=51678ksi · Bx= 12.5+ OA = 12.5+5.678 Tox = 18.178 lei And, Oys 1215-0A = 12,5 –

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